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3 years ago

There are two numbers one number is twice the other number

Mathematics

1 answer:

ololo11 [35]3 years ago

7 0

Let one number be x
therefore the other number is 2x

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An artists builds a sculpture out of metal and wood that weighs 14.9 kilograms.3/4 of this weight is metal,and the rest is wood.

Softa [21]

Given is a sculpture that is built up of metal and wood, and the weight of this sculpture is 14.9 kilograms.

It says that three-fourth of the total weight is metal and says to find the weight of wooden part.

We can find the weight of metal part and then subtract it from the total weight to calculate the answer.

Total weight = 14.9 kilograms.

Metal part = three-fourth of total weight = $\frac{3}{4} *14.9=\frac{44.7}{4} =11.175 \;kilograms$

Wooden part = 14.9 - 11.175 = 3.725 kilograms.

Hence, the wooden part is 3.725 kilograms.

7 0

2 years ago

Read 2 more answers

Find the measure of ∠2.<br><br> and how did you find the answer??

Rufina [12.5K]

The 2 lines are parallel, so the 2 sides(e.g. 1 and 2/ 3 and 49) add up = 180 and In this case the 2 sides are equal as u can see from the original diagram so the angle of 2 is 180-49=131.

5 0

3 years ago

Can someone help me understand this? Because I really don’t understand this at all

Otrada [13]

Answer: I believe it is A OR B

Step-by-step explanation: BECAUSE IF A⇒B AND B⇒C

THEN ¬A⇒C I THINK ITS A THO

OR ¬A⇒¬C

7 0

3 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

2 years ago

Which 2 statements are correct

GaryK [48]

A would be the correct ans

4 0

3 years ago