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Firlakuza [10]
3 years ago
15

Which pair of numbers has a gcf of 3

Mathematics
1 answer:
Ne4ueva [31]3 years ago
7 0
It would be the numbers 
15 or 28


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If quadrilateral ABCD is a parallelogram, what are the correct values for x and y? x = 30, y = 3 x = 30, y = 2 x = 70, y = 2 x =
jeka57 [31]

Answer:

-70 is the correct answer

Step-by-step explanation:

To add fractions, find the LCD and then combine

4 0
3 years ago
Read 2 more answers
Given line t passes through (0,-5) and (-1,3) and liner passes through (-4,3) and (4,2).
kupik [55]

Answer:

neither

Step-by-step explanation:

Slope of the first line: (y2 -y1)/(x2-x1) = (3-(-5)/-1 = 8/-1 = -8

Slope of the second line: (2-3)/4-(-4) = -1/8

They are neither parallel nor perpendicular. In fact the two lines have different slope so they can’t be parallel. In addition the product of their slope is not -1, so they can’t be perpendicular,

3 0
3 years ago
Can someone help me with this 4 - 3m > -5
ella [17]

Answer: M < -3

.................................................

Step-by-step explanation:

4 - 3m > -5

4 - 3m > (-4 -5)

3m > -9

(3/3)m > (-9/3)

m<-3

4 0
3 years ago
What is the coefficient of 4(3)(2)Q​
inysia [295]

Answer:

24

Step-by-step explanation:

4 x 3 = 12

12 x 2= 24

Coefficient is the number infront of the varible being multiplied. In this case 24 is the coefficient, and Q is the variable.

7 0
3 years ago
In another state, all license plates consist of from four to six symbols chosen from the 26 letters of the alphabet together wit
fredd [130]
A)
First note that the plates can have between 4 and 6 symbols so we will need to find the number of plates with 4 symbols, 5 symbols and 6 symbols. We add these to get the total. In this part repetition of symbols is allowed. Since there are 26 + 10 =36 possible symbols we look at each position on the plate and think of how many choices there are. We multiply the number f choices using the counting principal since the choices are each independent -- one symbol does not affect another. There are 36 choices for the first symbol, 35 for the second and so on. The number of plates is:
4-symbols = (36)(36)(36)(36)=36^4
5 symbols = (36)^5
6 symbols = 36^6
So the total here is: 36^4+36^5+36^6

B) Here we do not repeat symbols so there are 36 choices for the first symbol but only 35 for the next and 34 for the one after and so on.
4-symbols = (36)(35)(34)(33)
5 symbols = (36)(35)(34)(33)(32)
6 symbols = (36)(35)(34)(33)(32)(31)
So the total here is: (36)(35)(34)(33)+(36)(35)(34)(33)(32)+(36)(35)(34)(33)(32)(31)

c)
In order for there to be a repeated symbol we have 36 choices for the first symbol, 36 for the next and so on. However, for the last symbol we have to pick from one of the ones already selected so there are 3, 4 or 5 choices respectively.
4-symbols = (36)(36)(36)(3)
5 symbols = (36)(36)(36)(36)(4)
6 symbols = (36)(36)(36)(36)(36)(5)
So the total here is: (36^3)(3)+(36^4)(4)+(36^5)(5)

D)
The probability is given by (the number of plates with at least one repeated symbol)/(the total number of plates if repetitions are allowed) = (the answer to c) / (the answer to a)
3 0
3 years ago
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