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Jobisdone [24]
4 years ago
10

Find parametric equations for the line through the point (0, 2, 2) that is parallel to the plane x + y + z = 4 and perpendicular

to the line x = 1 + t, y = 2 − t, z = 2t.
Mathematics
1 answer:
Oxana [17]4 years ago
5 0

Answer: X = 3t, Y =2 - t, Z =2

Step-by-step explanation: the plane

x + y + z =4has normal vector

M =<1,1,1> and the line

x = 1 + t, y = 2 − t, z = 2t has direction

v =<1, −1, 2>. So the vector

A= n × v

=<1, 1, 1> × <1, −1, 2>

=<2−(−1),1−2,−1−1>

=<3,−1,−2>

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2/9x+-2=6 <br> i need help anyone?
Diano4ka-milaya [45]

Answer:

x = 36

Step-by-step explanation:

We have the equation (2/9)x + -2 = 6.

First, notice that adding a negative number is the same as subtracting by that number. So:

(2/9)x + -2 = 6

(2/9)x - 2 = 6

Now, we need to isolate the variable. Add 2 to both sides to cancel out the -2 on the left:

(2/9)x -2 + 2 = 6 + 2

(2/9)x = 8

Now multiply both sides by 9/2 to cancel out the 2/9 on the left:

(9/2) * (2/9)x = 8 * (9/2)

x = 72/2 = 36

Thus, x = 36.

<em>~ an aesthetics lover</em>

4 0
3 years ago
Due tomorrow! Please
svp [43]
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8 0
3 years ago
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vivado [14]

Answer:

Step-by-step explanation:

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6 0
3 years ago
Describe the location of the point having the following coordinates. positive abscissa, positive ordinate Quadrant I Quadrant II
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8 0
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The speed of the current in a creek is 5 mph. A person clan kayak 3 mi upstream in the same time that it takes him to kayak 13 m
Brut [27]

Answer:

8

Step-by-step explanation:

0) the basic formula is: L=v*t, where L - distance, v - speed/velocity; t - time;

1) if the person's speed in still water is 'v' and the speed of water is 5 (according to the condition), then the upstream speed is 'v-5' and the downstream speed is 'v+5';

2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

3) according to the items above it is possible to make up the equation of the upstream travel: t(v-5)=3; ⇒ t=3/(v-5);

4) according to the items above it is possible to make up the equation of the downstream travel: t(v+5)=13; ⇒ t=13/(v+5);

5) if t=3/(v-5) and t=13/(v+5), then

\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.

8 0
3 years ago
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