An equilateral shape is a shape that has all congruent sides.
<em>Sandy has a greater probability of selecting an equilateral shape</em>
Given
Sandy: <em>Equilateral triangle, Rhombus, and Regular hexagon</em>
Robert: <em>Scalene triangle, Kite, Isosceles trapezoid, Non-special quadrilateral, and Obtuse isosceles triangle</em>
All three shapes in Sandy's shape bucket are equilateral.
So, the probability that Sandy picks an equilateral shape is 1
All five shapes in Robert's shape bucket are non-equilateral.
So, the probability that Robert picks an equilateral shape is 0
By comparing the probabilities:
<em>1 is greater than 0</em>
Hence, Sandy is more likely to pick an equilateral shape than Robert.
Read more about probabilities at:
brainly.com/question/24297863
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Answer:
DF is your answer. Hope this helps!
Step-by-step explanation:
You have to show the top of the page!!
First you wanna see how many times 6 goes into 41 which is goes into 6 time so you would write 6 above the 1, then you would subtract 41-36 then it leaves you with 5 so you put it under the subtraction problem then add a zero to it and see how many times 6 goes into fifty which is 8 times so write 48 under the subtraction problem and it would be 2 so you add a zero now put a decimal after the 69. Like so then put 6 and put the infinite bar over the 6 tenths only and there you have it should be 69.6
