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mixer [17]
3 years ago
6

Michael is using a drawing program to complete a construction. Which construction is he completing? A circle is drawn with two p

erpendicular lines constructed inside. An equilateral triangle inscribed in a circle A square inscribed in a circle A regular pentagon inscribed in a circle A regular hexagon inscribed in a circle

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
3 0
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
We would need 3 points for an equilateral triangle, 5 for a pentagon, and 6 for a hexagon, which do not fit the current steps.

vovangra [49]3 years ago
3 0

Answer: A square inscribed in a circle

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Answer:

<h2>(4x+z)=13000------1</h2><h2>(4x+z)13000=503000----2</h2>

Step-by-step explanation:

let x be the number of seats in A,

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3 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
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Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

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3 years ago
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Answer:

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Step-by-step explanation:

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