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3 years ago

Jessie needs 36 eggs. Cartons of 12 eggs cost $2.75 each. How much does Jessie need to spend for 36 eggs

Mathematics

2 answers:

7nadin3 [17]3 years ago

7 0

Answer: $8.25 is your answer.

Step-by-step explanation:

12 x 3 = 36

2.75 for 12 so 2.75 times 3 = 8.25

kipiarov [429]3 years ago

6 0

Answer:

$8.25

Explanation:

If 12 eggs cost £2.75,

3 x 12 = 36,

$2.75 x 3 = $8.25.

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Sue Shopper received a $749.25 discount loan to purchase a refrigerator. The loan was offered at 12% for 120 days

STALIN [3.7K]

The interest paid for the loan will be:
I=(PRT)/100
P=$749.25
R=12%
T=120 days=120/30=4 months=1/3 years
Hence:
I=(749.25×1/3×12)/100
I=$29.97

The proceeds will be:
Net proceeds=(gross proceeds)-(expenses)
=749.25-29.97
=$719.28

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3 years ago

What is the amount paid for an $150 pair of shoes after a discount of 30% is applied?

Sloan [31]

Answer:

105

Step-by-step explanation:

150-30%= 105

Have a wonderful day!

3 0

3 years ago

Read 2 more answers

What is the solution to the system below? X=7

Olegator [25]

Answer:

A)(7,-9)

Step-by-step explanation:

we know x=7

so put it in the equation

y= -2(7)+5

y=-9

we always put the x coordinate first and then the y coordinate so the answer is (7,-9)

8 0

3 years ago

WILL GIVE BRANLIEST! pls help thank u sm!! :-) u are all amazing

Andrews [41]

Answer:

Step-by-step explanation:

Given

3 $(x+9)^{\frac{3}{4} }$ = 24 ( divide both sides by 3 )

$(x+9)^{\frac{3}{4} }$ = 8

Raise both sides to the power of $\frac{4}{3}$

x + 9 = $8^{\frac{4}{3} }$ = $(\sqrt[3]{8}) ^{4}$ = $2^{4}$ = 16 ( subtract 9 from both sides )

x = 7 → C

5 0

3 years ago

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

3 years ago