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3 years ago

Find the lenght of XY if W is between X and Y, WX= 38 and WY = 16.

Mathematics

2 answers:

Pepsi [2]3 years ago

7 0

Answer:

XY=54

Step-by-step explanation:

--x------------------------w------------------------Y--

38 16

To find XY you would add WY and WX because they are both in the line XY, if that makes sense.

XY=WX+WY

XY=38+16

XY=54

Hope this helped!!!

Dennis_Churaev [7]3 years ago

3 0

Answer:

XY = 54

Step-by-step explanation:

You are solving for the length of XY, in which it is given that W is in between point X and point Y. So essentially the line segment would be like XWY.

It is given to you that line segment WX is 38, and line segment WY is 16.

Set the equation:

WX + WY = XY

Plug in the corresponding numbers to the corresponding terms:

38 + 16 = XY

XY = 38 + 16

XY = 54

54 is your length for XY.

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Answer:

Step-by-step explanation:

$\sqrt{15}\\=3.87298\dots \\\\= 4$

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3 years ago

Mrs. Nixon went to the store to buy candy for her

AnnyKZ [126]

Answer:

$2.25

Step-by-step explanation:

First, we (always) highlight key details. In this case, we would highlight that th candy is 90 cents per pound, and the she bought 2.5 pounds. Now, we just multiply 2.5 by .90, and boom! We get $2.25. Mrs. Nixon spent $2.25 (or two dollars and twenty-five cents) on candy bars.

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3 years ago

Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.

Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

$y=ax^2+bx+c$

Here the vertex of an up - down facing parabola has a form of,

$x_v=-\dfrac{b}{2a}$

The parameters we have are,

$a=-5,b=-10, c=6$

Plug them in vertex formula,

$x_v=-\dfrac{-10}{2(-5)}=-1$

Plug in the $x_v$ into the equation,

$y_v=-5(-1)^2-10(-1)+6=11$

We now got a point parabola vertex with coordinates,

$(x_v, y_v)\Longrightarrow(-1,11)$

From here we emerge two rules:

If $a$ then vertex is max value
If $a>0$ then vertex is min value

So our vertex is minimum value since,

$a=-5\Longleftrightarrow a$

Hope this helps.

r3t40

7 0

3 years ago

A-attached earlobes a-unattached earlobes if a is the allele for having attached earlobes, what percentage of offspring will hav

Scorpion4ik [409]

The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.

What is a Dominant Trait?

A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.

Given the following traits:

A - attached earlobes (dominant allele)

a - unattached earlobes (recessive allele)

A cross between Aa and aa is shown in the image attached below.

The offspring having attached earlobes = 2 Aa = 50%.

50% of the osspring will have attached earlobes.

Learn more about dominant trait on:

brainly.com/question/16616523