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3 years ago

7848 / 4 what Is the quotient

Mathematics

1 answer:

andriy [413]3 years ago

8 0

$\text{Hey there!}$

$\text{Both numbers are divisible to 4, so divide the numerator and denominator from 4}$

$\frac{7,848\div4}{4\div4}$

$\text{7,848}\div4=1,962$

$\text{4}\div4=1$

$\text{1,962}\div1=1,962$

$\boxed{\boxed{\text{Answer: 1,962}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

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2 years ago

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Sandra sells necklaces at a school craft fair. She uses the equation P= 7.5n - (2.25n + 15) to determine her total profit at th

gregori [183]

The way you find profit is to subtract the revenue and the cost
Profit = Revenue - Cost
The revenue is the amount of money coming in, the cost is the amount of money going out. The goal of course is to have the revenue larger than the cost so that the profit is positive.

So the equation given is
P = 7.5n - (2.25n+15)
and its in the form
P = R - C
where...
R = 7.5n is the revenue equation
C = 2.25n+15 is the cost equation

Focus on the revenue equation
R = 7.5n
which is the same as
R = 7.50*n

This tells us that Sandra pulls in a total of 7.50*n dollars where n is some positive whole number. It represents the number of necklaces sold. For example, if she sold n = 10 necklaces, then
R = 7.50*n
R = 7.50*10
R = 750
meaning that Sandra has made $750 in revenue

As you can see above, the revenue is computed by multiplying the price per necklace ($7.50) by the number of necklaces sold (n) to get R = 7.50*n

So that's why the answer is $7.50

Note: The 2.25 is part of the cost equation. This is known as the variable cost. It is the cost to make one necklace ignoring the fixed cost (eg: rent). The variable cost often doesn't stay the same, but algebra textbooks often simplify this aspect.

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3 years ago

How to do this cause I'm very lost

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3 years ago

Solve for the given length. The length of a rectangle is 3m longer than its width. The area of the rectangle is 154^2. What is t

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If the length of a rectangle is 3m longer than its width, then:
L=W+3
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A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m

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