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Ivahew [28]
3 years ago
12

Find the solution of the system of equations shown on the graph, Enter the correct answer

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

(0,4)

Because you look at both point they only come across each other at (0,4)

MissTica3 years ago
4 0

Answer: (0,4)

Explanation: What you're looking for is their point of intersection.

The point where the two lines intersect is the solution to the system.

In this case, the to lines intersect at the point (0,4).

So (0,4) is the solution to the system.

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What is 1/2 • 1 • 2 please help
BabaBlast [244]

Answer:

1

Step-by-step explanation:

1/2x1x2

1

8 0
2 years ago
What is 7/8 + 1/2 as a fraction
forsale [732]

Answer:

11/8 is the answer as a fraction

4 0
4 years ago
Margo’s dog, named Todd, weighed 120 pounds last year. She now weighs 180 pounds. What is the percent of change
elixir [45]

Answer:

50%

Step-by-step explanation:

the increase is 60 so divide that by the original number; 60/120=0.5

now we have to change the decimal to a percent. multiply by 100 to do that and we get 50%.

3 0
3 years ago
Read 2 more answers
Missing some of the data points in the sample is a:
shutvik [7]

Answer:

Measurement error.

Step-by-step explanation:

Measurement Error are the error when there is difference found in true value of data and measured quantity of data. This difference could be found if we are missing some data in the sample.

The error could be reduced by carefully designing the process of data collection and it´s measurement.

Measurement error are classified into two type of error:

  1. Random error.
  2. Systematic error.
5 0
3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
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