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mash [69]
3 years ago
6

HELP I NEED HELP ASAP

Mathematics
1 answer:
Allisa [31]3 years ago
5 0

Answer:

3x^2-6x+3=0

x^2-2x+1=0

x^2-x-x+1=0

x(x-1)-(x-1)=0

(x-1)(x-1)=0

x=1,1

so x has only one answer

so it intersects only one time

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Does anyone know how to solve this?
Ivahew [28]

Answer:

Multiplay 30 by 5 Then multiply five-by-five then Multiply 20 by 5 Then take away your answer

7 0
3 years ago
-6(2r +8)=-10(r-3)<br> I need the work to
barxatty [35]

Answer:

r = -39

Step-by-step explanation:

So we are trying to solve the equation for r.

-6(2r + 8) = -10(r - 3)

Divide both sides by -2. (This will make distributing much easier.)

3(2r + 8) = 5(r - 3)

Distribute the 3 on the left side and the 5 on the right side,

6r + 24 = 5r - 15

Subtract 24 from both sides.

6r = 5r - 39

Subtract 5r from both sides.

r = -39

So now we have solve the equation.

I hope you find my answer and explanation to be helpful. Happy studying. :)

5 0
3 years ago
Solve Highschool Pre cal
Bezzdna [24]

Option C:

\ln 64 y^{2}

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule a \log b=\log b^{a}  in the above expression.  

⇒ 2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}

Applying log rule \log a+\log b=\log (a b) in the above expression.

⇒ \ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)

We know that 8^{2}=64

⇒ \ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}

Hence, the expression in single natural logarithm is \ln 64 y^{2}.

6 0
3 years ago
In an arithmetic series, the sum of the first 12 terms is equal to ten times the sum of the first 3 terms. If the first term is
arlik [135]

Answer:

Step-by-step explanation:

The formula for determining the sum of the first n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

If a = 5, the expression for the sum of the first 12 terms is

S12 = 12/2[2 × 5 + (12 - 1)d]

S12 = 6[10 + 11d]

S12 = 60 + 66d

Also, the expression for the sum of the first 3 terms is

S3 = 3/2[2 × 5 + (3 - 1)d]

S3 = 1.5[10 + 2d]

S3 = 15 + 3d

The sum of the first 12 terms is equal to ten times the sum of the first 3 terms. Therefore,

60 + 66d = 10(15 + 3d)

60 + 66d = 150 + 30d

66d + 30d = 150 - 60

36d = 90

d = 90/36

d = 2.5

For S20,

S20 = 20/2[2 × 5 + (20 - 1)2.5]

S20 = 10[10 + 47.5)

S20 = 10 × 57.5 = 575

8 0
3 years ago
What is the percent of change from 6,000 to 60?
Thepotemich [5.8K]

Answer: 99% decrease

Step-by-step explanation: Since the number changes from 6,000 to 60, we know that it's decreasing. Now to find the percent decrease, we divide the amount of change by the original number.

The amount of change is the difference between 6,000 and 60 and the original number is 6,000.

6,000 - 60 is 5,940 so we are left with \frac{5,940}{6,000} and dividing 6,000 into 5,940 gives us 0<em>.</em>99.

Finally, since the problem is asking us for the <em>percent</em>, we write 0.999 as a percent by moving the decimal point 2 places to the right to get 99%.

So when a number changes from 6,000 to 60, it has decreased by 99%.

6 0
3 years ago
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