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2 years ago

HELP I NEED HELP ASAP

Mathematics

1 answer:

Allisa [31]2 years ago

5 0

Answer:

3x^2-6x+3=0

x^2-2x+1=0

x^2-x-x+1=0

x(x-1)-(x-1)=0

(x-1)(x-1)=0

x=1,1

so x has only one answer

so it intersects only one time

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8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please

Leya [2.2K]

Answer:

$(2m - 7)(4 {m}^{2} + 3)$

Step-by-step explanation:

$8m^3 - 28m^2 + 6m - 21 \\ = 4 {m}^{2} (2 {m} - 7) + 3(2m - 7) \\ = (2m - 7)(4 {m}^{2} + 3)$

4 0

2 years ago

12+[ 9 4/5 - ( 1.5 + 2 2/10)] Someone please help me?

lord [1]

Answer:

18.1

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3 years ago

What is the solution to q+(-9)=12

Whitepunk [10]

q−9=12

Step 1: Add 9 to both sides.

q−9+9=12+9

q=21

Answer:

q=21

7 0

3 years ago

Read 2 more answers

Log_{7 }(5 - 3x) Find the derivative

V125BC [204]

Let y be the expression you want to differentiate:

$y=\log_7(5-3x) \implies 7^y=5-3x$

Now,

$7^y=e^{\ln(7^y)}=e^{y\ln(7)}$

Use the chain rule to differentiate both sides with respect to x :

$\ln(7)e^{y\ln(7)}\dfrac{\mathrm dy}{\mathrm dx}=-3$

Solve for dy/dx :

$\ln(7)7^y\dfrac{\mathrm dy}{\mathrm dx}=-3$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac3{\ln(7)7^y}$

$\dfrac{\mathrm dy}{\mathrm dx}=\boxed{-\dfrac3{\ln(7)(5-3x)}}$

6 0

2 years ago

assume that a 3 month CD purchased for $2000 pay a simple interest at an annual rate of 10%. How much total interest does it ear

algol [13]

CD = certificate of deposit (an investment)
Interest rate, i = 10% per annum (simple interest)
Principal, P = $2000 (present value)
Period, T = 3 months = 0.25 year

Simple interest formula
Interest earned = Pit
=2000*0.10*0.25
=$50

Balance at maturity (amount that investor gets after three months)
=$2000+$50
=$2050

7 0

3 years ago