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2 years ago

Identify the missing number 41, 48,33,40,62,55,54,?,

Mathematics

2 answers:

Nat2105 [25]2 years ago

7 0

Answer:

can I get how you solved it

AlladinOne [14]2 years ago

5 0

Answer:

Hope it helps

Please mark me as the brainliest

Thank you

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The mean sustained wind velocity, v, can be determined by the equation , where p is the air pressure, in millibars, at the cente

inn [45]

The mean sustained wind velocity has the equation:

v = 6.3 √(1013 - p)

If we are given with the mean sustained wind velocity of 64 m/s, then we can solve for the air pressure using the equation:

64 = 6.3 √(1013 - p)

64/6.3 = √(1013 - p)

10.1587² = 1013 - p

p = 910 millibars

hope this helps!!!!!!!!!!!!

8 0

3 years ago

Read 2 more answers

Consider the equation Y=-2x+5 Create a table of five ordered pairs that satisfy the equation. What is the slope of the line repr

Vikentia [17]

Five pairs of points (X,Y) that satisfy the equation Y=-2X+5 may be the following:

For X=0: Y=-2*0+5=5 (0,5)

For X=1: Y=-2*1+5=3 (1,3)

For X=2: Y=-2*2+5=1 (2,1)

For X=3: Y=-2*3+5=-1 (3,-1)

For X=4: Y=-2*4+5=-3 (4,-3)

The slope of the function is m=-2. Correct answer: C

5 0

3 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

3 years ago

The daily supply of oxygen for a particular multicellular organism is provided by 625 feet of lawn. A total of 3,750 square feet

Ainat [17]

Answer:

The answer to your question is 6 organisms.

Step-by-step explanation:

Data

625 ft² -------- 1 multicellular organism

3750 ft² -- number of organisms

Process

1.- To know the number of organisms that can supply 3750 ft² of lawn, we need to use proportions and cross multiplication.

625 ft² ------------------ 1 multicellular organisms

3750 ft² ------------------ x

x = (3750 x 1) / 625

x = 3750 / 625

x = 6

2.- Conclusion

3750 ft² can supply of oxygen 6 organisms.

5 0

3 years ago

How do you solve this? My algebra 2 teacher taught it to us in class but it still confuses me! Thank you!

nataly862011 [7]

$\bf \cfrac{\frac{1}{8}-\frac{1}{2x}}{\frac{1}{12x}-\frac{1}{3x^2}} \begin{array}{llll} \leftarrow \textit{our LCD here will just be }8x\\[0.9em] \leftarrow \textit{our LCD down here will be }12x^2 \end{array}$

$\bf \cfrac{~~\frac{(x)1-(4)1}{8x}~~}{\frac{(x)1-(4)1}{12x^2}}\implies \cfrac{~~\frac{x-4}{8x}~~}{\frac{x-4}{12x^2}}\implies \cfrac{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{\underset{2}{~~\begin{matrix} 8x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{3x}{~~\begin{matrix} 12x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{~~\begin{matrix} x-4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \cfrac{3x}{2}$

8 0

3 years ago

Identify the missing number 41, 48,33,40,62,55,54,?,​

Identify the missing number 41, 48,33,40,62,55,54,?,