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Pie
2 years ago
6

How do I find the area ASAP

Mathematics
1 answer:
Arlecino [84]2 years ago
7 0

Answer:


Step-by-step explanation:

a=\frac{h_{b}b }{2} \\

·\frac{13·17}{2}

a=110.5


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I don’t understand any of this and its dude tomorrow someone help ;)
faltersainse [42]
You should get the app "photomath" that'll help you out alot!!!
6 0
3 years ago
For each sequence, find a general term <br> 13. 1,3,5,7,9
mafiozo [28]
The next number is 11, counting by 2’s
4 0
3 years ago
2x+5y=12
anastassius [24]
Y = -3x - 1......so we sub in -3x - 1 in for y in the other equation

2x + 5y = 12
2x + 5(-3x - 1) = 12....now distribute the 5 through the parenthesis
2x - 15x - 5 = 12...add 5 to both sides
2x - 15x = 12 + 5..combine like terms
-13x = 17...divide both sides by -13
x = -17/13
now sub in -17/13 for x in the other equation
y = -3x - 1
y = -3(-17/13) - 1
y = 51/13 - 1
y = 51/13 - 13/13
y = 38/13

so the solution is (-17/13, 38/13)

8 0
3 years ago
A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are
lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

H_0: \mu_1 - \mu_2 = 0

H_a: \mu_1 - \mu_2 > 0

In which \mu_1 is the mean pine trees height while \mu_2 is the mean spruce trees height.

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

X = 35 - 30 = 5

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2

s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{5 - 0}{2.4495}

z = 2.04

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

8 0
3 years ago
How many decimeters are there if there are 3 centimeters.
Shtirlitz [24]
There are .3 decimeters in 3 centimeters
7 0
3 years ago
Read 2 more answers
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