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disa [49]
3 years ago
11

Antar is flying a triangular-shaped kite. It has a height of 4 1/2 feet and a base of 5 3/4 feet. What is the area of Antar's ki

te?
Mathematics
2 answers:
kotykmax [81]3 years ago
8 0
Area\ of\ triangle: \\  \frac{1}{2}bh \\  \\  \frac{1}{2}(4.5\ feet)(5.75\ feet) \\  \\ \boxed{12.9375\ feet^{2}}
Ostrovityanka [42]3 years ago
3 0
The answer to your question is: 12.9375

A=1/2bh
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36ft

Explanation: 6x6=36
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Find the area of the circle.
juin [17]

Answer:

See Explanation Below

Step-by-step explanation:

Your question isn't clear; However, I'll solve in two ways

1. Diameter = 14 cm

2. Radius = 14 cm

<em></em>

<em>When Diameter = 14 cm</em>

Given

Area = \pi r^2

Diameter = 14cm

Required

Calculate the area of the circle

First, the radius has to be solved;

Radius = \frac{1}{2} Diameter

Radius = \frac{1}{2} * 14cm

Radius = 7cm

Using the given formula;

The area is as follows

Area = \pi r^2

Area = 3.14 * 7^2

Area = 3.14 * 49

Area = 153.86cm^2

<em>When Radius = 14 cm</em>

Given

Area = \pi r^2

Radius = 14cm

Required

Calculate the area of the circle

Using the given formula;

The area is as follows

Area = \pi r^2

Area = 3.14 * 14^2

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7 0
3 years ago
Right Triangles and Trigonometry Homework 5
gavmur [86]

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4 0
3 years ago
A typical cup of coffee contains about 100 mg of caffeine and every hour approximately 16% ofthe amount of caffeine inthe body i
Over [174]

Answer:

a) \frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

b) C(5) = 100 e^{-0.16*5}= 44.9329

Step-by-step explanation:

Part a

For this case we can assume the proportional model given by:

\frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

Part b

For this case we can replace the value t=5 into the model and we got:

C(5) = 100 e^{-0.16*5}= 44.9329

7 0
3 years ago
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