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disa [49]
4 years ago
11

Antar is flying a triangular-shaped kite. It has a height of 4 1/2 feet and a base of 5 3/4 feet. What is the area of Antar's ki

te?
Mathematics
2 answers:
kotykmax [81]4 years ago
8 0
Area\ of\ triangle: \\  \frac{1}{2}bh \\  \\  \frac{1}{2}(4.5\ feet)(5.75\ feet) \\  \\ \boxed{12.9375\ feet^{2}}
Ostrovityanka [42]4 years ago
3 0
The answer to your question is: 12.9375

A=1/2bh
You might be interested in
What is the factors of x2-x-12
Otrada [13]

Answer: ( x − 3 ) ( x + 4 )

Step-by-step explanation:

7 0
4 years ago
Someone please help on this one?? :(
zaharov [31]

Answer:

C F(x) = -(x+4)^3

Step-by-step explanation:

When we reflect across the x axis, the equation becomes - f(x)

so (x+4)^3  becomes -(x+4)^3

5 0
4 years ago
Rectangle ABCD is congruent to rectangle URST.
Triss [41]

The area of the rectangle URST is 135 mm². so the option C is correct.

<h3>What are Congruent rectangles?</h3>

Congruent rectangles have the same lengths of sides, same measures of angles and same areas and same perimeters

The Rectangle ABCD is congruent to rectangle URST

Given; Rectangle ABCD ≅ rectangle URST

AB = UR , BC = RS , CD = ST , AD = UT

AB = 9 millimeters

UR = 9 millimeters

We know that, The area of any rectangle = l × w,

In rectangle URST

∵ UR = 9 millimeters

∵ RS = 15 millimeters

- Assume that UR = l and RS = w

The area of rectangle URST = UR × RS

The area of rectangle URST = 9 × 15 = 135 millimeters²

Hence, The area of rectangle URST is 135 mm²

Learn more about rectangle here;

brainly.com/question/13307509

#SPJ1

4 0
2 years ago
Help please.
yarga [219]
The correct answer is D
6 0
3 years ago
Help I will give you brainliest if you do
Elenna [48]

Answer:

Step-by-step explanation:

If the position function is

h(t)=-40t^2+200t and we are looking for time when the height is 0, we sub in a 0 for h(t) and solve for t:

0=-40t^2+200t and the easiest way to do this is to factor by taking the GCF of -40t:

0 = -40t(t - 5) and by the Zero Product Property,

-40t = 0 or t - 5 = 0. Solving for t, we get

t = 0 (which is before the object is launched) and

t = 5 (which is how long it takes the object to go from the ground, up to its max height, and then back to the ground again).

Your choice is c) 5

7 0
3 years ago
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