Answer: (
x
−
3
)
(
x
+
4
)
Step-by-step explanation:
Answer:
C F(x) = -(x+4)^3
Step-by-step explanation:
When we reflect across the x axis, the equation becomes - f(x)
so (x+4)^3 becomes -(x+4)^3
The area of the rectangle URST is 135 mm². so the option C is correct.
<h3>What are Congruent rectangles?</h3>
Congruent rectangles have the same lengths of sides, same measures of angles and same areas and same perimeters
The Rectangle ABCD is congruent to rectangle URST
Given; Rectangle ABCD ≅ rectangle URST
AB = UR , BC = RS , CD = ST , AD = UT
AB = 9 millimeters
UR = 9 millimeters
We know that, The area of any rectangle = l × w,
In rectangle URST
∵ UR = 9 millimeters
∵ RS = 15 millimeters
- Assume that UR = l and RS = w
The area of rectangle URST = UR × RS
The area of rectangle URST = 9 × 15 = 135 millimeters²
Hence, The area of rectangle URST is 135 mm²
Learn more about rectangle here;
brainly.com/question/13307509
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Answer:
Step-by-step explanation:
If the position function is
and we are looking for time when the height is 0, we sub in a 0 for h(t) and solve for t:
and the easiest way to do this is to factor by taking the GCF of -40t:
0 = -40t(t - 5) and by the Zero Product Property,
-40t = 0 or t - 5 = 0. Solving for t, we get
t = 0 (which is before the object is launched) and
t = 5 (which is how long it takes the object to go from the ground, up to its max height, and then back to the ground again).
Your choice is c) 5
