Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
solve for y
The solution of the inequality A is the shaded area above the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
----> inequality B
The solution of the inequality B is the shaded area below the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
Using a graphing tool
The solution of the system of inequalities in the attached figure
Answer:
1058.4 in^2
Step-by-step explanation:
Find the surface areas of the rectangular prism and the triangular prisms separately.
Triangular: S = (1/2)lP+B, where l is slant height, P perimeter, and B base area.
14(4)= 56 perimeter of base
13 slant height
B = 14x14 = 196
put together:
S = (1/2)(13 x 56) + 196
S = 560 in^2
Now the rectangular prism
S = 2lw + 2lh + 2wh, where l is length, h height, w width. (delete the first 2lw since they share one side/they're combined shapes.
S = 2(14x8.9) + 2(14x8.9)
S = 498.4 in^2
Add them together: 498.4 + 560 = 1058.4 in^2
Hello!
In order to find how many boys there are in the class simply subtract 67 from 146:
146-67= 79
There are 79 boys in the class
I hope it helps!
