Q11
Suppose the two numbers are x and y so xy = 3000
the HCF = 10
we know that product of two numbers = product of their HCF and LCM
XY = HCF * LCM
3000 = 10 * LCM
3000/10 = LCM
300 = LCM
Answer 300
Q12 : Let us say second number is x so
product of x and 160 = product of HCF and LCM of ( x and 160 )
160 x = 32 * 1760
x= 32 * 1760 / 160
x= 352
Answer : 352
The ratio of the geeses to ducks will be 11:12 because there are 11 geeses and 12 ducks :)
Answer:
Explanation:
From the question, we are told that a pet shop sells guinea pigs and goldfish and that the ratio of guinea pigs to goldfish is 20:28.
a) Give this ratio in its simplest form.
The ratio of guinea pigs to goldfish is 20:28. The highest common factor to 20 and 28 is 4. Therefore 20 = 4 × 5 and 28 = 4 × 7. So, the ratio in its simplest form will be 5:7.
b. The shop has a total of 120 guinea pigs and fish. Work out the number of guinea pigs the shop has.
The ratio of guinea pig and goldfish is 5:7. If the shop has a total of 120 guinea pigs and fish, the number of guinea pigs the shop has will be:
= 5/12 × 120
= 5 × 10
= 50 guinea pigs
The slope-intercept form of a line is:
y=mx+b, where m=slope and b=y-intercept (value of y when x=0)
First you must find the slope, or m value.
m=(y2-y1)/(x2-x1), which is the change in y divided by the change in x. In this case:
m=(5--3)/(-4--1)
m=(5+3)/(-4+1)
m=8/-3
m=-8/3
So far our line is:
y=-8x/3+b, we can now solve for the y-intercept, or b, using any point on the line, I'll use (-4,5):
5=-8(-4)/3+b
5=32/3+b
15/3=32/3+b
15/3-32/3=b
-17/3=b
So now we know the value for both terms in our line:
y=(-8x-17)/3
Assuming that the null hypothesis is true, then<u> p-Value</u> is the probability of observing a value of the test statistic that is at least as extreme as the value actually computed from the sample data.
Step-by-step explanation:
<u>The p-value is the probability that a random sample that is selected produces as the value of the test statistic is at least as extreme as the observed value when H0 is true.</u>
<u>The p-value as measure of how surprising our result is if the null hypothesis is true.</u>
So ,we can state that- Assuming that the null hypothesis is true, then<u> p-Value</u> is the probability of observing a value of the test statistic that is at least as extreme as the value actually computed from the sample data.
