Answer: R = {0, -3, -9, 5, 7}
Explanation: The range is the set of all y-coordinates for our ordered pairs.
So the range for this relation is {0, -3, -9, 5, 7}.
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
4 meters
tons and grams are mass measurements
kilometer is closer to a mile measurement
so the only one that makes sense is 4 meters
3x2(4x<span> – 3) + 1(4</span>x<span> – 3) </span>
Answer:
0.60
Step-by-step explanation:
In the category of pets
22 students had a cat = P(C)
17 students had a dog = P(D)
9 students had both a dog and a cat = P(C and D)
The formula to find the Probability of two events =
P(C or D) = P(C) + P(D) - P(C and D)
P(cat or dog) = P(cat) + P( dog) - P(cat and dog)
P(cat or dog) = 22/50 + 17/50 - 9/50
P(cat or dog) = 0.44 + 0.34 - 0.18
P(cat or dog) = 0.60
The probability the student will have a dog or a cat is 0.60
