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2 years ago

The booster club now raises $0.41 for each pom pom they sell.

2 answers:

4 0

Steps:
0.41p=50
Divide both sides by 0.41
0.41/0.41 cancels out.
50/0.41 = 121.951

You can’t sell 121.951 Pom Poms.
So

Answer:

0.41p=50

122 Pom poms

VLD [36.1K]2 years ago

3 0

If you do .41x122 you get 50

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When addressing an envelope for delivery in the United States or Canada, the zip code should appear

levacccp [35]

ZIP codes are codes utilized for the purpose of postal and adhering to the postal system. This contributes to faster process of delivering to and from the send and receiver of the mails. ZIP codes do not just apply on countries worldwide, but this also applies to the places inside these countries. Provinces and cities and have their own ZIP codes assigned to them in accordance to the ZIP code assigned to the country. This is why most mails should have a ZIP code attached to the mail and to the letter when being delivered whether it is locally delivered or internationally delivered. When addressing an envelope for delivery in the United States or Canada, the ZIP code should appear on the same line as the city and state. So the answer to the question above would be B.

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3 years ago

The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate

Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The margin of error is:

$MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

Given:

$\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90$

The critical value of z for 90% confidence level is:

$z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645$ *Use a standard normal table.

Compute the sample size required as follows:

$MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910$

Thus, the sample size required is 910.

5 0

3 years ago

In 4 games, Larry averaged 23 PPG (points per game). How many points does he need to score in the last game to have an average o

ivann1987 [24]

Larry needs to score 33 points in the last game to have an average of 25 PPG.

To find the answer, we can solve the equation:

$\frac{(4)23+p}{5}=25$

(where p is how many points he needs to score in the last game)

To find the mean of a group of numbers, you add them all up and divide the total by the number of numbers there are. Since Larry averaged 23 PPG in 4 games, we can multiply 23 by 4 to get the total of the first 4 games from the data. Then, we find p, which we will add to get our final total. Then, you divide by the 5 games.

$\frac{(4)23+p}{5}=25$
$\frac{92+p}{5}=25$
${92+p}=125$
$p=33$

First, I simplified 4 x 23 to get 92. Then, I multiplied each side by 5 to get rid of the denominator. Finally, I subtracted 92 from each side to isolate p, and found that p = 33.

8 0

3 years ago

Read 2 more answers

Six Flags Amusement Park has found that 3/5 of its customers ride the Colossus roller coaster. Of these, 1/4 ride it again. What

QveST [7]

Answer:

The answer is B. 3/20

Step-by-step explanation:

That will be 1/4 of 3/5

3/5 × 1/4

3/20

3 0

3 years ago

In Lixue’s garden, the green pepper plants grew 5 inches in 34 month. At this rate, how many feet can they grow in one month? (L

beks73 [17]

Answer:

<h2>0.15 inches per month</h2>

Step-by-step explanation:

step one:

This problem is focused on the growth rate of a plant.

given data

the plants grow 5 inches in 34 months

and also that 1 month= 4 weeks

step two:

We can still say that

if 34 months see a growth of 5 inches

then 1 months will be X inches

cross multiply we have

X= 5/32 inches

step three:

converting this number to decimal we have

X= 0.15 inches per month

Therefore the growth rate would be

0.15 inches per month

5 0

3 years ago