How much work is required to lift a 600-kg satellite to an altitude of 1⋅1061⋅106 m above the surface of the earth? The gravitat
ional force is ????=????????m/????2F=GMm/r2, where ????M is the mass of the earth, mm is the mass of the satellite, and ????r is the distance between them. The radius of the earth is 6.4⋅1066.4⋅106 m, its mass is 6⋅10246⋅1024 kg, and in these units the gravitational constant, ????G, is 6.67⋅10−11
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Answer: Hello your question is poorly written attached below is the complete question
answer:
0.1515
Step-by-step explanation:
Number of bets = 200
mean number of losses = $0.2
Standard deviation = $2.74
<u>Determine P ( winning after 200 bets ) </u>
Average of 200 bets > 0. i.e. P( X > 0 )
considering normal distribution : μ = -0.2 , б = 2.74 , n = 200
applying Z - distribution
z = 0 - ( - 0.2 ) / ( 2.74 / √200 ) ≈ 1.03
∴ P ( z > 1.03 ) = 1 - P ( z < 1.03 )
= 1 - 0.8485 ( value gotten from z-table )
= 0.1515
