Answer:
60
Step-by-step explanation:
Tangents to a circle from a common external point are congruent, thus
JA = JB = 6
AL = KC = 11
CK = KB = 13
Thus
perimeter = 2(6) + 2(11) + 2(13) = 12 + 22 + 26 = 60
Answer:
g=-4
Step-by-step explanation:
2g+6-14g=-6(g-5)
-12g+6=-6g+30
-6g+6=30
-6g=24
g=-4
The mean would be 7 I think I am not sure
The <em><u>correct answer</u></em> is:
bx + 3y > 6 and y > 2x + 4
Explanation:
Looking at the second inequality, the y-intercept is 4 and the slope is 2. This means the graph of the line crosses the y-axis at (0, 4) and the line goes up 2 and over 1. Since it is greater than, this means the graph is shaded above it. Comparing this to the graph, the line for the blue part crosses the y-axis at (0, 4) and goes up 2 and over 1. The graph is also shaded above the line.
For the first inequality, bx+3y > 6, we want to isolate y. To do this, we subtract bx from each side:
bx+3y-bx > 6-bx
3y > 6-bx
Divide both sides by 3:
3y/3 > 6/3 - bx/3
y > 2 - (b/3)x
This means the line for this will have a y-intercept of 2 and decrease 1 while going over 3. The orange section does this. Additionally, since it is greater than, the graph should be shaded above the line. This one is, so this is the correct answer.
