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lina2011 [118]
3 years ago
5

9(3+c+4) what is the answer

Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer:

the answer is 9c+63

Step-by-step explanation:

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I need help with this question. If you find the answer tell me how you got it.
alina1380 [7]
17 3/4 - 2/5x = 4 1/2
-2/5x = 4 1/2 - 17 3/4
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-2/5x = 18/4 - 71/4
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x = (-53/4) / (-2/5)
x = -53/4 * - 5/2
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4 years ago
A used CD is a dollar more than one third the price of a new CD. If a new CD costs $18, how much is a used CD
Veseljchak [2.6K]

Answer:

6

Step-by-step explanation:

8 0
3 years ago
Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin
Anastasy [175]

Suppose y_2(x)=y_1(x)v(x) is another solution. Then

\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}

Substituting these derivatives into the ODE gives

x^2(v''x^3+6v'x^2+6vx)-x(v'x^3+3vx^2)-3vx^3=0

x^5v''+5x^4v'=0

Let u(x)=v'(x), so that

\begin{cases}u=v'\\u'=v''\end{cases}

Then the ODE becomes

x^5u'+5x^4u=0

and we can condense the left hand side as a derivative of a product,

\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C

x^5u=C\implies u=Cx^{-5}

Solve for v:

v'=Cx^{-5}\implies v=-\dfrac{C_1}4x^{-4}+C_2

Solve for y_2:

\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}

So another linearly independent solution is y_2=\dfrac1x.

3 0
3 years ago
Please help and graph it I need this done in 2 minut s pleasee
My name is Ann [436]
Go to a website called desmos it’s a graphing calculator and you just type what you want graphed and it shows it
3 0
3 years ago
What is 4+2 x { 16/ (5+3)} 2
Dahasolnce [82]
The answer for you problem is 6
4 0
3 years ago
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