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Vadim26 [7]
3 years ago
7

Simple math question

Mathematics
2 answers:
ra1l [238]3 years ago
8 0

Answer:

All squares have 4 equal angles

Step-by-step explanation:

squares are always even, whilst rectangles have 2 diff lengths

Anon25 [30]3 years ago
7 0

Answer:

All squares have four equal angles

Step-by-step explanation:

Every square must have four equal angles to be a square

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The image point of A after a translation right 4 units and down 4 units is the point B(12, – 7). Determine the coordinates of th
natita [175]

Answer:

<h3>             (8, –3)</h3>

Step-by-step explanation:

Translation right or left means change of the x-coordinate.  

Translation up or down means change of the y-coordinate.

Translation right or up means adding.

Translation left or down means  subtracting.

A=(x_A, y_A)\quad\rightarrow\quad B=(x_A+4,\,y_A-4)\\\\x_A+4=12\qquad\qquad y_A-4=-7\\\\x_A=12-4\qquad\qquad y_A=-7+4\\\\x_A=8\qquad\qquad\qquad y_A=-3\\\\A=(8,-3)

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3 years ago
What is the unit price if you divide 5.36 by 20 oz?
Alisiya [41]

Answer:

$0.27 per oz

I hope this helps :)

5 0
3 years ago
Help me fast for the brsainliest answer
xxMikexx [17]

Answer:

b.21

Step-by-step explanation:

increass by +2,+3,+4,+5,+6

7 0
3 years ago
Read 2 more answers
GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
4 years ago
Which expression is equivalent to r^9/r^3?<br> O r^3<br> O r^6<br> O r^12<br> O r^27
valkas [14]

Answer:

r^12 no r^6

Step-by-step explanation:

I was wrong it is r^6 r−9(−3) r−9+3=r−6

  • r-6 becomes 1 over r6

5 0
2 years ago
Read 2 more answers
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