G = m/5t- Q^2. Hope that helps.
<h3>Exact answer: x = 35/3 (fraction form)</h3><h3>Approximate answer: x = 11.667 (decimal form)</h3>
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Explanation:
The inscribed angle AHP is exactly half that of the arc it cuts off, which is arc AP = 160.
inscribed angle = (1/2)*(arc measure)
angle AHP = (1/2)*(arc AP)
6x+10 = (1/2)*160
6x+10 = 80
6x = 80-10
6x = 70
x = 70/6
x = 35/3
x = 11.667 approximately
<em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>