If the quadrilateral below is a rhombus, find the missing measures.

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

corner angles are 80° (∠JKL) and 100° (∠MJK)
side lengths are 2√61

Step-by-step explanation:

The given length measures are the diagonals of the rhombus, so each side will be the hypotenuse of the triangle with legs half as long:

√(12² +10²) = √244 = 2√61 ≈ 15.62 . . . . side length

The given angle measure is half the measure at ∠J. The full measure of ∠J is 100°, so the measure of ∠K is 180° -100° = 80°

You might be interested in

Help me please answer thanks

nasty-shy [4]

Answer:

8, 2

Step-by-step explanation:

8 * 2 = 16

8 + 2 = 10

6 0

3 years ago

Look at the picture for the question please show work.

lukranit [14]

$A=\dfrac{1}{2}ah\\
a=25 \text{ mm}\\
h=14 \text{ mm}\\\\
A=\dfrac{1}{2}\cdot25\cdot14\\
A=175 \text{ mm}^2 \Rightarrow C$

6 0

3 years ago

Let f(x)=cos(x)x^-2<br> F’(x)=

kondaur [170]

$f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}$