We have the following system of equations:
y = -6x-6
y = x2-5x-6
Matching we have:
x2-5x-6 = -6x-6
Rewriting we have:
x2-5x-6 + 6x + 6 = 0
x2 + x = 0
Rewriting:
x (x + 1) = 0
The solutions are:
x = 0
x = -1
For x = 0
y = -6 (0) -6 = 0-6 = -6
y = -6
For x = -1
y = -6 (-1) -6 = 6-6 = 0
y = 0
The solutions are:
(x, y) = (0, -6)
(x, y) = (- 1, 0)
Answer:
The solutions of the system are:
(-1, 0) and (0, -6)
The questions seems to be lacking some information. By rate I'm going to assume position and in that scenario the answer would be B because the position function is modeled by a linear function.
Sometimes true, depends on d. ex: -8 + -8 is negative, but -8 + 9 is positive
Answer:
26
Step-by-step explanation:
18 + 8 = 26
Given:
Mason throws a coin 3 times.
The outcome of each throw is either Heads or Tails.
To find:
The list of all the possible outcomes of the 3 throws.
Solution:
Let H represents heads and T represents tails.
For each throw we have 2 choices either H or T.
For three throws the total number of possible outcomes is
Now, list the possible outcomes as shown below.
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
Therefore, the list of 8 possible outcomes is HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.
