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Oduvanchick [21]
3 years ago
12

4 equals 2 m -5 n 4 m

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0
M = 6 - 5n hope this helps
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13 Answer:
Marizza181 [45]

Step-by-step explanation:

13.

132 miles in 3 h = 132miles/3hours = 132/3 miles/h =

= 44 miles/h

so,

how long for 110 miles ?

speed = distance/time

time = distance/speed = 110 miles / 44 miles/h =

= 110/44 h = 55/22 h =

= 5/2 h = 2.5 h

14.

60% = 60/100 = 6/10 = 3/5

15.

300% = 300/100 = 3

16.

116 2/3% = (348 + 2)/3% = 350/3% = 350/3/100 =

= 350/300 = 1 50/300 = 1 1/6

17.

19% = 19/100

18.

3.8% = 3.8/100 = 38/1000 = 19/500

19.

166 2/3% = (498 + 2)/3% = 500/3% = 500/3/100 =

= 500/300 = 5/3 = 1 2/3

20.

4/5 = 0.8 = 80%

21.

7/4 = 1.75 = 175%

22.

1/3 = 0.3333333... ≈ 33.33%

23.

2 = 200/100 = 200%

24.

0.4 = 40%

25.

0.375 = 37.5/100 = 37.5%

26.

80% of 60 = 60×80/100 = 60×4/5 = 48

27.

24% of 65 = 65×24/100 = 65×6/25 = 13×6/5 =

= 15.6

28.

115% of 138 = 138×115/100 = 138×23/20 =

= 69×23/10 = 158.7

29.

18.3% of 74 = 74×18.3/100 = 74×183/1000 =

= 37×183/500 = 13.542 ≈ 13.54

30.

6.5% of 115 = 115×6.5/100 = 115×65/1000 =

= 23×13/40 = 7.475 ≈ 7.48

31.

0.75% of 93 = 93×0.75/100 = 93×75/10000 =

= 93×3/400 = 0.6975 ≈ 0.70

4 0
1 year ago
If a cereal box (rectangular prism) has the dimensions of 6 inches by 4 inches by 14 inches, what is the volume?
musickatia [10]

Answer:

the volume is 336

6 0
3 years ago
Read 2 more answers
9,032,504.75 in word form
vodka [1.7K]
Nine million thirty-two thousand five hundred four and seventy-five hundredths
6 0
3 years ago
Read 2 more answers
Everyday Erin’s Orange stand uses 1 3/8 bags of oranges for how many days will 5 1/2 bags of oranges last
lana [24]

Answer:

0.0625 Days

Step-by-step explanation:

For 1 day Erin uses 1 3/8

1 day consumption is 11/8

11/2 bags of oranges would take

11/2 divided by 11/8

5 0
2 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
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