Step-by-step explanation:
13.
132 miles in 3 h = 132miles/3hours = 132/3 miles/h =
= 44 miles/h
so,
how long for 110 miles ?
speed = distance/time
time = distance/speed = 110 miles / 44 miles/h =
= 110/44 h = 55/22 h =
= 5/2 h = 2.5 h
14.
60% = 60/100 = 6/10 = 3/5
15.
300% = 300/100 = 3
16.
116 2/3% = (348 + 2)/3% = 350/3% = 350/3/100 =
= 350/300 = 1 50/300 = 1 1/6
17.
19% = 19/100
18.
3.8% = 3.8/100 = 38/1000 = 19/500
19.
166 2/3% = (498 + 2)/3% = 500/3% = 500/3/100 =
= 500/300 = 5/3 = 1 2/3
20.
4/5 = 0.8 = 80%
21.
7/4 = 1.75 = 175%
22.
1/3 = 0.3333333... ≈ 33.33%
23.
2 = 200/100 = 200%
24.
0.4 = 40%
25.
0.375 = 37.5/100 = 37.5%
26.
80% of 60 = 60×80/100 = 60×4/5 = 48
27.
24% of 65 = 65×24/100 = 65×6/25 = 13×6/5 =
= 15.6
28.
115% of 138 = 138×115/100 = 138×23/20 =
= 69×23/10 = 158.7
29.
18.3% of 74 = 74×18.3/100 = 74×183/1000 =
= 37×183/500 = 13.542 ≈ 13.54
30.
6.5% of 115 = 115×6.5/100 = 115×65/1000 =
= 23×13/40 = 7.475 ≈ 7.48
31.
0.75% of 93 = 93×0.75/100 = 93×75/10000 =
= 93×3/400 = 0.6975 ≈ 0.70
Nine million thirty-two thousand five hundred four and seventy-five hundredths
Answer:
0.0625 Days
Step-by-step explanation:
For 1 day Erin uses 1 3/8
1 day consumption is 11/8
11/2 bags of oranges would take
11/2 divided by 11/8
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.