The semi-annual net cash flow the company must achieve in order for the purchase to be made is $2500.
<h3>How to calculate the cash flow?</h3>
Number of period = 6 × 2 = 12
Rate = 4% / 2 = 2%
Annual cash flow × PVIFA × (2% × 12) + $7500 × PVIF(2%,12) - $32348 = 0
Annual cash flow × 10.5753 = $32348 - $7500 × 0.7885
Annual cash flow × 10.5753 = $32348 - $5914
Annual cash flow × 10.5753 = $26434
Annual cash flow = 26434/10.5753
Annual cash flow = $2500
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12.
12x3 is already 36, more than 30..
Answer:
4.5
Step-by-step explanation:
The median we know is the middle number of a set of numbers. Putting the set in least to great order, we have (1, 3, 3, 6, 8, 9). The middle number here is 3 and 6. We take the mean of 3 and 6, (3+6)/2 which gives us 4.5 and that is our answer.
Answer:
Step-by-step explanation:
2/cos^2(theta) - sin^2(theta)/cos^(theta) = p
(2 - sin^2(theta) ) / cos^2(theta) = p
cos^2(theta) = 1 - sin^2(theta) Relationship between sines and cosines
2 - sin^2(theta)/ (1 - sin^2(theta) ) = p Everything is now in terms of sines
sin^2 (theta) = 1 / csc ^2 (theta) sin^(theta) = 1/csc(theta)
2 - 1/csc^2(theta) Make Left over csc(theta)
============== = p
1 - 1/csc^2(theta)
2 csc^2(theta) - 1
------------------------
csc^2(theta)
================ = p Cancel out denominators (csc^2(theta))
csc(theta) - 1
-------------------
csc^2(theta)
2 csc^2 (theta) - 1
=============== = p Multiply both sides by csc^2(theta) - 1
csc^2(theta) - 1
2csc^2(theta) - 1 = p*csc^2(theta) - p Collect csc^2(theta) on the left, p on the right.
csc^2(theta) (2 - p) = 1 - p
csc^2(theta) = (1 - p)/(2 - p)
Answer:
May 10th she had the most debt and may 20 she had the most in her bank