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postnew [5]
3 years ago
8

What is the general form of the equation of the line shown?

Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer:

y-2=0 is the correct answer. thanks

Step-by-step explanation:


Artyom0805 [142]3 years ago
5 0

Answer:

Option A is correct.

General form of the equation of the line:  y-2 = 0

Step-by-step explanation:

The general form of the equation is given by:

y = mx +b where m is the slope and b is the y-intercept.

y-intercepts of the line is the value of y at the point where the line crosses the y-axis(i.e x= 0)

From the given figure;

we can see that the line crosses the y-axis at y =2  and also here the slope is , m= 0

therefore, by definition of y-intercepts

y-intercept (b) = 2

Therefore, the equation of line as shoen in figure is:

y = (0)x + 2

or

y = 2

y-2 = 0

Therefore, the general form of the equation line as shown in the figure is:

y-2 =0

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Answer:

Step-by-step explanation:

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h=6×90/100=5.4 in

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c.

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2 years ago
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Answer:


Step-by-step explanation:

The question will look like (3b)/(a^-2)

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3 years ago
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Answer:

Length of the bold arc = 72.63 ft

Step-by-step explanation:

Length of the arc = \frac{\theta}{360}(2\pi r)

Here, θ = angle subtended by the arc at the center

r = Radius of the circle

Since, angle subtended by the bold arc at the center = 360 - 73

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By substituting these values in the formula,

Length of the bold arc = \frac{287}{360}\times (2\pi)(14.5)

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3 years ago
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