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2 years ago

What is the value (ratio) of cos A? A. 8/15 B. 15/17 C. 15/8 D. 8/17

Mathematics

2 answers:

TEA [102]2 years ago

8 0

Cos A=8/17
the ans is D

forsale [732]2 years ago

3 0

Cos A = $\frac{adjacent}{hypotenuse}$ = $\frac{AB}{AC}$ = $\frac{8}{17}$

Answer: D

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago

In a game of pool, a 0.4 kg cue ball is traveling at 0.80 m/s when it hits a slower striped ball moving at 0.38 m/s. after the c

LiRa [457]

The magnitude of the final velocity of the cue ball is (B) 0.56m/s.

<h3>What is Velocity</h3>

The definition of velocity is a vector measurement of the rate and direction of motion.
It is a moving body's speed and direction of motion.

How to calculate the magnitude of the final velocity?

The magnitude of the final velocity can be calculated by following the steps:

The mass of the cue ball given is 0.4kg.
The velocity of the cue ball given is +0.80m/s.
The velocity of the striped ball before the collision is +0.38 m/s.
The velocity of the striped ball after collision is +0.62m/s.
We need to find the magnitude of the final velocity of the cue ball.

Assuming all pool balls have the same mass: 0.4kg

Let the final velocity of the cue ball be x.

Now, To find the final velocity:

Mass of the cue ball × initial velocity of cue ball + Mass of striped ball + initial velocity of striped ball = mass of cue ball × final velocity + mass of striped ball × final velocity of the striped ball

(0.40)×(0.80)+(0.4)(0.38) = (0.4)(x)+(0.4)(0.62)
0.32+0.152=0.4x+0.248
0.472=0.4x+0.248
0.472-0.248= 0.4x
0.224/0.4 =x
x = 0.56m/s

Therefore, the magnitude of the final velocity of the cue ball is (B) 0.56m/s.

Know more about velocity here:

brainly.com/question/25749514

#SPJ4

The correct question is given below:

In a game of pool, a 0.4 kg cue ball is traveling at +0.80 m/s when it hits a slower striped ball moving at +0.38 m/s. After the collision, the striped ball moves off at +0.62 m/s. What is the magnitude of the final velocity of the cue ball? Assume all pool balls have the same mass.

A. 0.20 m/s

B. 0.56 m/s

C. 1.0 m/s

D. 1.8 m/s

3 0

5 months ago

Can anyone answer these problems?

inna [77]

I can answer these problems

3 0

3 years ago

Answer???? Angle 1, and angle 2. I need help

REY [17]

M> 1 + m>2 = 90°
x-12 + 5x = 90°
6x - 12 = 90°
6x -12 +12 = 90°+12
6x = 102
6x/6 = 102/6
x = 17

m>1 = x-12
m>1 = 17-12
m>1 = 5

m>2 = 5x
m>2 = 5(17)
m>2 = 85

7 0

2 years ago

Find the value of x (circles)

Marrrta [24]

Answer:

x = 55

Step-by-step explanation:

opposite angles are supplementary

125+x = 180

Subtract 125 from each side

125+x-125 = 180-125

x = 55

6 0

2 years ago

Read 2 more answers