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S_A_V [24]
4 years ago
10

Please help!!!! For each set of given points A, B, C, and D on a number line, find the distances AB, BC, AC, and BD: A(–3); B(5)

; C(–12); D(–13)
Mathematics
1 answer:
PIT_PIT [208]4 years ago
7 0

Answer:

AB=8 BC=17 AC=9 BD=18

Step-by-step explanation:

Okay, so A is -3 and B is 5, so the distance would be 8, because the difference between -3 and 5 is 8. The same goes for all the rest. The distance on the number line is the difference between the two numbers they represent.

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PLEASE HELP WILL GIVE BRAINLIEST
OleMash [197]

Answer: y = -2x - 1, b = -1

Step-by-step explanation:

  • y = mx + b
  • -3 = 1(-2) + b
  • -3 = -2 + b
  • -1 = b

7 0
3 years ago
Mixed number fraction 7and1/5+3and2/5
PtichkaEL [24]

Answer:

53/5 = 10 3/5

Step-by-step explanation:

convert both to fraction

7x5 + 1 = 36

3x5 + 2 = 17

36 + 17 = 53

actually you could have just added

7 + 3 = 10

1 + 2 = 3 for the fraction

3 0
4 years ago
Please help thank you so much
Licemer1 [7]

Answer:

\Huge\boxed{x=15}

Step-by-step explanation:

Hello There!

The angle labeled 6x is a right angle

If an angle is formed using the diameter of a circle then the opposite angle of that side is a right angle

So 6x = 90

isolate the variable

divide each side by 6

90/6= 15

6x/6=x

we're left with x = 15

5 0
3 years ago
Read 2 more answers
A national manufacturer of ball bearings is experimenting with two different processes for producing precision ball bearings. It
lapo4ka [179]

Answer:

A. As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

B. t=-3.144

C. The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

D. P-value = 0.004

E. Reject H0

F. The probability of making a Type I error is equal to the significance level: P(Type I error) = 0.05.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the two processes yield different average errors.

As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

being  μ1: average error for Process A and μ2: average error fo Process B.

The significance level is 0.05.

The sample 1, of size n1=12 has a mean of 2 and a standard deviation of 1.

The sample 1, of size n1=14 has a mean of 3 and a standard deviation of 0.5.

The difference between sample means is Md=-1.

M_d=M_1-M_2=2-3=-1

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1^2}{12}+\dfrac{0.5^2}{14}}\\\\\\s_{M_d}=\sqrt{0.083+0.018}=\sqrt{0.101}=0.318

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-1-0}{0.318}=\dfrac{-1}{0.318}=-3.144

The degrees of freedom for this test are:

df=n_1+n_2-1=12+14-2=24

The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

This test is a two-tailed test, with 24 degrees of freedom and t=-3.144, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the two processes yield different average errors.

5 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST TO THE FIRST PERSON THAT ANSWER PLEASE
user100 [1]

Answer:

a) x = k \times \frac{1}{y^2} \ , \ where \ k \ is \ a \ constant\\\\b) x = 3, \ when\  y\  =\  10\\\\c) y = 10, \ when \ x = 3

Step-by-step explanation:

a)

x \ \alpha  \ \frac{1}{y^2}\\\\x = k \times \frac{1}{y^2}\\\\                [ \ where \ k \ is \ a \ constant \ ]

<em><u>Find k.</u></em>

Given x = 12, y = 5,

12 = k \times \frac{1}{5^2}\\\\k = 12 \times 25 = 300

b)

<em><u>Find x.</u></em>

Given y = 10

We have k = 300

x = k \times \frac{1}{y^2}\\x = 300 \times \frac{1}{10^2} \\\\x= \frac{300}{100} = 3

c)

<u><em>Find y</em></u>

Given x = 3

We have k = 300

x = k \times \frac{1}{y^2}\\\\3 = 300 \times \frac{1}{y^2}\\\\\frac{1}{y^2} = \frac{3}{300}\\\\\frac{1}{y^2} = \frac{1}{100}\\\\y^2 = 100\\\\y = \sqrt{100}  = 10

8 0
3 years ago
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