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aliya0001 [1]
3 years ago
11

What is the x- and y-intercepts of -x-y=1/2

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0
X(-1/2,0) y(0,-1/2) will complete this
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Find all solutions <br> 36x²+12x=0
FromTheMoon [43]

Answer:

x = -1/3 or 0

Step-by-step explanation:

Given equation:

  • 36x^{2}  + 12x = 0

We can factor 12x on the L.H.S since 12x is divisible by 36x² and 12x.

\implies 36x^{2}  + 12x = 0

\implies 12x(3x + 1) = 0

This can lead to two solutions. I have listed them below!

<h2>Solution 1:</h2>

Divide 12x on both sides to open the parentheses.

\implies 12x(3x + 1) = 0

\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}

<em>Note: zero divided by any non-zero number is 0.</em>

\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}

\implies 3x + 1 = 0

Isolate 3x on one side of the equation.

\implies 3x + 1 = 0

\implies 3x = 0 - 1

\implies 3x = -1

Divide 3 both sides to determine the value of x.

\implies 3x = -1

\implies \dfrac{3x}{3} = \dfrac{-1}{3}

\implies \boxed{x = \dfrac{-1}{3}}

<h2>Solution 2:</h2>

Divide (3x + 1) on both sides to isolate 12x.

\implies 12x(3x + 1) = 0

\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}

<em>Note: zero divided by any non-zero number is 0.</em>

\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}

\implies 12x = 0

Divide 12 both sides to determine the value of x.

\implies 12x = 0

\implies \dfrac{12x}{12}  = \dfrac{0}{12}

\implies \boxed{x = 0}

Therefore, the solutions for x are -1/3 or 0.

Learn more about this topic: brainly.com/question/295675

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