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dusya [7]
4 years ago
14

22 fl oz=how many cups and fl oz

Mathematics
2 answers:
igomit [66]4 years ago
5 0
1 cup = 8 fl oz.

So then we can set up a ratio of \sf \frac{fluid ~ounces}{cups}

So we get:

\sf\frac{8~ fl. oz.}{1 ~cup} =  \frac{22 ~fl. oz.}{x~ cups}

We cross multiply and we try to solve for x, so:

\sf 8~fl.~oz. \times x ~cups = 1~cup \times 22~fl.~oz.

\sf x~cups =  \frac{22~fl.oz.}{8~fl.oz.}

And the fl. oz. cancel out, and we are left with:

\sf x~cups =  \frac{22}{8} =  \frac{11}{4} = 2 \frac{3}{4}

<u>So 22 fl. oz. equals to 2 3/4 cups.</u>




Darina [25.2K]4 years ago
5 0
2.75 cups
8 oz = 1 cup
22/8 = 2.75 cups
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Students at Salt Lake Community College pay 1.667 * 104 dollars for tuition.Students at George Washington University pay 5.5011
podryga [215]

Answer:

its rigged 1234

Step-by-step explanation:

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5 0
3 years ago
what is the solution to the system of equations: x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10
ladessa [460]

Given equations are x- - y-z = 2, - x - 3 y - 2 z + 4, -x - 2 z = 10 .

It seems you have missed to write = in the 2nd equation so i have fixed the sign and going to solve the following system of equations:

x-y-z=2 ...(i)

-x-3y-2z=4 ...(ii)

-x-2z=10 ...(iii)


solve (i) for x

x=2+y+z ...(iv)

plug (iv) into (ii)

-x-3y-2z=4

-(2+y+z)-3y-2z=4

-2-y-z-3y-2z=4

-2-4y-3z=4

-4y-3z=6...(v)


plug (iv) into (iii)

-x-2z=10

-(2+y+z)-2z=10

-2-y-z-2z=10

-2-y-3z=10

-y=12+3z

y=-12-3z...(vi)


plug (vi) into (v)

-4y-3z=6

-4(-12-3z)-3z=6

48+12z-3z=6

48+9z=6

9z=-42

z=-14/3


Now plug value of z into (vi)

y=-12-3z=-12-3(-14/3)=-12+14=2

y=2


plug value of y and z into (iv)

x=2+y+z=2+2-14/3=-2/3


Hence final answer is x=-2/3, y=2, z=-14/3

3 0
3 years ago
Help solving this math question
olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = \frac{488,106,000-358,708,000}{2} = \frac{129,398,000}{2} = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = \frac{4,051,050}{5,921,379} = 0.6841,

Agricultural / natural resources ratio = \frac{373,904}{488,106} = 0.766,

Education's ratio = \frac{2,164,607}{3,008,036} = 0.7196,

General government's ratio = \frac{14,347,325}{14,716,155} = 0.9749,

Highways and transportation's ratio = \frac{1,468,482}{1,773,893} = 0.827,

Public safety's ratio = \frac{263,463}{464,233} = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

4 0
3 years ago
Help me plz and thank you
stiks02 [169]

Answer:

nopee. Try your best you will get the answer.

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP PLEASEEE THANKS!!
Kryger [21]
Its A. hipe this helps
7 0
3 years ago
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