Question

Write expression as one circular function ​

Answer 1

Answer:

$\cos^2 x$

Step-by-step explanation:

$\dfrac{\cos^2 x \sin^2 x}{\tan^2 x(1 - \sin^2 x)} =$

$= \dfrac{\cancel{\cos^2 x} \sin^2 x}{\tan^2 x\cancel{\cos^2 x}}$

$= \dfrac{\sin^2 x}{\tan^2 x}$

$= \dfrac{\sin^2 x}{\dfrac{\sin^2 x}{\cos^2 x}}$

$= \sin^2 x \times \dfrac{\cos^2 x}{\sin^2 x}$