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3 years ago

What do the double brackets with an x in the middle mean?

Mathematics

1 answer:

borishaifa [10]3 years ago

8 0

That is an absolute value. (the accual magnitude of a numerical number) it look like a v when graphed.

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By the Triangle Inequality Theorem which set of side lengths could create a triangle? A) 4, 8, 2 B) 5, 9, 6 C) 6, 8, 16 D) 10, 4

Mazyrski [523]

The answer is B. For a triangle to be possible, no side can be longer than the sum of the lengths of the other two sides. For triangle A, 8 is longer than 4+2, so it is not possible. For triangle B, no side is greater than the sum of the other sides, so it is possible. For triangle C, 16 is greater than 6+8, so it is not possible. For triangle D, 10 is greater than 4+3, so it is not possible.

6 0

3 years ago

Read 2 more answers

If you apply the changes below to the quadratic parent function, Ax) = x2,

sdas [7]

Answer:

Please use "^" to denote exponentiation.

Start with f(x) = x^2. Shifting the graph of f(x) 1 unit to the left results in

g(x) = (x+1)^2.

Vertically stretching the graph of g(x) by a factor of 3 results in

h(x) = 3(x+1)^2.

Reflecting h(x) over the x-axis results in k(x) = -3(x+1)^2

Step-by-step explanation:

6 0

3 years ago

X / 12 equals 27 / 33

Alexxandr [17]

What is your question?

5 0

3 years ago

Each pair of polygons is similar. Find each missing side measure. two polygons 12 on top 5 on bottom second polygon 48 on top x

Firlakuza [10]

Answer:

$x = 20$

Step-by-step explanation:

Given

First Polygon:

$Top = 12$

$Bottom =5$

Second Polygon

$Top = 48$

$Bottom =x$

Required

Find x

Since both polygons are similar, then:

$Ratio = Top:Bottom$

For the first:

$Ratio = 12:5$

For the second

$Ratio = 48:x$

Equate both ratios

$12:5 = 48:x$

Express as fraction

$\frac{12}{5} = \frac{48}{x}$

Cross Multiply

$12 * x = 48 * 5$

Solve for x

$x = \frac{48 * 5}{12}$

$x = \frac{240}{12}$

$x = 20$

4 0

3 years ago

Give the area of one of the triangles followed by the area of the small inner square separated by a comma. Express your answers

Ket [755]

The full question is: Given that the side of the square has a length b−a, find the area of one of the four triangles and the area of the small inner square.

Give the area of one of the triangles followed by the area of the small inner square separated by a comma. Express your answers in terms of the variables a and b.

Answer: (b-a)^2, {(b-a)^2}/4

Step-by-step explanation:

One side of the big square = b-a, therefore,

(total area of big square =(b-a)^2

The four inner triangles are equal because they are divided by diagonal lines of a square. So area of one triangle will be: area of square/4. So,

Area of each of 4 inner triangles= ( {b-a)^2} /4

From the image attached, I've drawn the diagram to reflect what the question is saying. The sides of the small inner square are connected by mid points of inner triangle sides.

By symmetry, we can tell that the area of this small square would be a quarter of that of the big square seeing that the sides of this small square will be half of the side of the big square.

Therefore, area of small square =

{(b-a)^2}/4

4 0

4 years ago