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3 years ago

The graph shows the amount of money the drama club raised based on the number of sweatshirts sold.

Mathematics

2 answers:

lawyer [7]3 years ago

7 0

The independent variable is the number of sweatshirts sold so it is answer A.

(Money raised is the dependent variable because it depends on the number of sweatshirts sold.)

Ivahew [28]3 years ago

5 0

Answer:

A) 1, 2, 3, 4, 5

Step-by-step explanation:

The graph shows the number of Sweatshirts sold and amount of money raised.

Here x-axis represents the number of Sweatshirts sod and y-axis represents the amount of money raised.

From the given graph, we infer cost of 1 Sweatshirt is $9.

2 Sweatshirts = $ 18

3 Sweatshirts = $27

4 Sweatshirts = $36

5 Sweatshirts = $45

Here the amount of money depends upon the number of Sweatshirts sold.

Here the number of Sweatshirts sold represents the independent variable and the amount of money raised represents the dependent variable.

So, independent quantities = 1, 2, 3, 4, 5.

Therefore, answer is A) 1, 2, 3, 4, 5

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Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

Product of 3 and d is 3×d = 3d.

The sum of six and the product of three and d is 6+3d.

Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

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2 years ago

Four time a number r plus half a number s equals 12. Twice the number r plus one fourth of the numbers s equals 8. What are the

Snezhnost [94]

The system of equations have no solution.

Explanation:

The equations are $4r+\frac{1}{2}s=12$ and $2r+\frac{1}{4} s=8$

To find the two numbers, let us solve the equations using substitution method.

From the equation $2r+\frac{1}{4} s=8$ , let us determine the value of r,

$\begin{aligned} 2 r+\frac{1}{4} s &=8 \\ 2 r &=8-\frac{1}{4} s \\ r &=\frac{1}{2}\left(8-\frac{1}{4} s\right) \\ r &=4-\frac{1}{8} s \end{aligned}$

Let us substitute the value of r in $4r+\frac{1}{2}s=12$ , we get,

$\begin{aligned} 4\left(4-\frac{1}{8} s\right)+\frac{1}{2} s &=12 \\ 16-\frac{1}{2} s+\frac{1}{2} s &=12 \\ 16 &=12 \end{aligned}$

which is not possible.

This means that the system has no solution.

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JulsSmile [24]

Answer:

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Step-by-step explanation:

difference means subtract

Number - 47

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