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MrRissso [65]
3 years ago
13

In a laboratory, scientist are performing chemical reactions.the amount of product formed by a reaction can be determined by equ

ation p= .25r find the constant of proportionality?tell me I’m desperate.
Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

  0.25

Step-by-step explanation:

The only constant in the equation is called the "constant of proportionality." Its value is 0.25.

The constant of proportionality is 0.25.

____

In an equation of the form ...

  y = kx

the constant k is called the <em>constant of proportionality</em>. It's a vocabulary (naming) question.

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Wht is the substitution of x+y=9 and x=2y
Rama09 [41]
I hope this helps you



2y+y=9



3y=9



y=3


x=2y=2.3=6
3 0
3 years ago
Solve for xx. Round to the nearest tenth, if necessary.
jasenka [17]

Step-by-step explanation:

S+T+U=180°{sum of angle of triangle}

  • 68°+90°+U=180°
  • U=180-158°
  • U=22°

sin theta= p/h

sin22°=x/83

o.37=x/83

x=0.37×83

x=30.71

x=31

stay safe healthy and happy.

6 0
2 years ago
Expand the expression by distributing <br> -2(-4x-7)
vova2212 [387]
-2(-4x-7)
Answer:
8x+14
6 0
3 years ago
Read 2 more answers
What is the answer to -4(-8x - 8)?
Naddika [18.5K]
You distribute the -4 with the -8x and -8 which results in 32x+32.
4 0
3 years ago
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A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4.
antiseptic1488 [7]

Answer:

<h2> 1.69</h2>

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

5 0
3 years ago
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