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2 years ago

8

How do i solve 2x+6>20

1 answer:

lukranit [14]2 years ago

4 0

Hello!

To solve 2x+6>20, you'll first need to subtract. First, you'll need to subtract 6 from 20 (20-6). Now if the 6 was negative, you would need to add 6 to 20, but for this equation you'll subtract.

2x>14

Now you will need to divide both sides by 2. Once you've done that you'll have your answer of...

x>7

I hope this helps!

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Step-by-step explanation:

Please see the attached picture.

Let's find the value of the opposite side, XZ.

Applying Pythagoras' Theorem,

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<em>Square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em>,</em>

XZ= $\sqrt{3969}$

XZ= 63 <em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(simplify)</em>

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