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2 years ago

What is the median of this data set? Enter your answer in the box. median =

Mathematics

1 answer:

bija089 [108]2 years ago

4 0

Answer:

Median = 2

Step-by-step explanation:

Median is basically what's the middle of a set of data.

There's a total of 9 numbers:

1.5, 1.5, 2, 2, 2, 2.5, 3, 3.5, 4

The repeated 2nd 2, is the median in this set of data.

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Christy purchased an art easel at a garage sale for $30. She later sold the easel on Craigslist for $45. What was the percent in

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2 years ago

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Given the following quadratic function what’s the value of a, B, and C?<br><br> f(x)= 3x^2 - 5x -12

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Answer:

Below.

Step-by-step explanation:

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3 years ago

At a video store, you have two options for renting movies. You can pay $4 per movie, or you can pay a one-time membership fee of

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Let x stand for a movie.

You can pay $4 every movie or $1.50 for every movie plus the original $10

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-1.50x -1.50x (Subtraction Property of Equality)

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/2.50 /2.50 (Division Property of Equality)

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3 years ago

Jenny likes to paint. She estimates the number of paintings she completes using the function P of w equals one half times w plus

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The answer to the question is A.

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3 years ago

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PLEAZZZZZZZZZZ HELP ASAP

stich3 [128]

QUESTION 1

GIVEN:

$long \: base = 3 \times (short \: base)$

$height = (short \: base) - 2$

$area = 30 {in}^{2}$

IMPORTANT EQUATIONS

$trapezoid \: area = \frac{sum \: of \: bases}{2} \times height$

SOLVE:

$30 = \frac{short + long}{2} (short - 2)$
$30 = \frac{(short + 3short)}{2} \times (short - 2)$

$30 = \frac{4short}{2} (short - 2)$

$30 = 2{(short)}^{2} - 4(short)$

${short}^{2} - 2(short) - 15 = 0$

factor:

$(short - 5)(short + 3) = 0$

$short = 3 \: and \: - 5$
Negative five is not a reasonable answer, so we focus on the positive three and say that is the length of the short base.

so, the answers:

$short \: base = 3 \: in$

$long \: base = 3 \times 3 = 9 \: in$

$height = 3 - 2 = 1 \: in$

QUESTION 2

GIVEN
convert 3ft to inches.

$l = 32 + w$

$area = lw = 130 {in}^{2}$
or

$w = \frac{130}{l}$

substitute

$l = 32 + \frac{130}{l}$

solve for l:

${l}^{2} - 32 l- 130 = 0$
QUESTION 3

$x(x + 2) = 80$

solve for X

${x}^{2} + 2x - 80 = 0$
$(x - 10)(x + 8) = 0$

$x = 10 \: and \: - 8$

take the positive value since it's the only one that makes sense in this context.

so the two values are:

$10 \: and \: 8$

8 0

3 years ago