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3 years ago

2×(5+2)÷2 what is the answer

Mathematics

2 answers:

vlada-n [284]3 years ago

8 0

The answer is 7, your welcome if this helped!

Hunter-Best [27]3 years ago

6 0

The answer is 7 because you add 2+5=7 then you times it by 2 which is 14 then divide by 2 which is 7 again.

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Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with

worty [1.4K]

Answer:

$z$

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean $\mu =26$ kilograms and standard deviation $\sigma=4.2$ kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

$X$ "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(26,4.2)$

Where $\mu=26$ and $\sigma=4.2$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

$z=\frac{42.6-26}{4.2}=3.95$

So then the corresponding z scale would be:

$z$

7 0

3 years ago

ANSWER ALL THREE I WILL MAKE YOU THE BRAINLIEST EASY QUESTION

Anna35 [415]

Number 1 is 14/10 number 4 is 3 1/7 number 5 is 3 5/6

4 0

3 years ago

Read 2 more answers

Flying against the wind, an airplane travels 3760 kilometers in 4 hours. Flying with the wind, the same plane travels 4320 kilom

Gemiola [76]

Answer:

1 hour each 30 minutes so the answer is 30 minutes

5 0

2 years ago

How do you simplify this

katen-ka-za [31]

It's 2/5 in decimal form it is 0.4.

5 0

3 years ago

Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d

Stella [2.4K]

The answer is most likely A.

The integration interval [a, b] is split up into n subintervals of equal length (so each subinterval has width (b - a)/n, same as the coefficient of the sum of y terms) and approximated by the area of n rectangles with base (b - a)/n and height y.

n subintervals require n + 1 points, with

x₀ = a

x₁ = a + (b - a)/n

x₂ = a + 2(b - a)/n

and so on up to the last point x = b. The right endpoints are x₁, x₂, … etc. and the height of each rectangle are the corresponding y 's at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function G(x) continuous* over an interval [a, b] is equal to the slope of the secant line through x = a and x = b, i.e. the value of the difference quotient

(G(b) - G(a) ) / (b - a)

If G(x) happens to be the antiderivative of a function g(x), then this is the same as the average value of g(x) on the same interval,

$g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx$

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [a, b] into n subintervals of equal width (b - a)/n. Over the first subinterval, the area of a trapezoid with "bases" y₀ and y₁ and "height" (b - a)/n is

(y₀ + y₁) (b - a)/n

but y₀ is clearly missing in the sum, and also the next term in the sum would be

(y₁ + y₂) (b - a)/n

the sum of these two areas would reduce to

(b - a)/n = (y₀ + 2 y₁ + y₂)

which would mean all the terms in-between would need to be doubled as well to get

$\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)$

7 0

3 years ago