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laila [671]
3 years ago
15

-3(x-4)=21 i know i’m asking a lot of questions but i CANT fail this math test

Mathematics
2 answers:
tigry1 [53]3 years ago
8 0

Hey there!

<h2>ANSWER: x=-3</h2><h2>EXPLANATION:</h2>

-3(x-4)=21

To solve, we will need to simplify this equation.

-3(x-4)=21\\

We will need to distribute.

(-3)(x)+(-3)(-4)=21\\\text{Equals:} -3x+12=21

Now we have to subtract 12 from both sides.

-3x+12-12=21-12\\\text{Equals:}-3x=9

In our last step, we have to divide both sides by -3 to get the answer.

\frac{-3x}{-3} =\frac{9}{-3}\\ \text{Equals: }x=-3

Hope this helps!

\text{Please rate this answer, or mark brainliest, and don't forget to thank!}\\\text{-TestedHyperr}

Law Incorporation [45]3 years ago
7 0

Answer:

x= -3

Step-by-step explanation:

mutliply the -3 to parentheses.

-3x+12 = 21

-3x = 21-12

/-3

x= 9/-3

x= -3

You might be interested in
Line m is parallel to line p. m ∠ HEF = 39º and m ∠ IGF = 13º. Find the m ∠ EFG. Explain in detail how you know you are correct.
svetlana [45]

Answer:

The measure of ∠EFG is 52°

Step-by-step explanation:

Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.

In ΔJFG,

By angle sum property of triangle, which states that sum of all angles of triangle is 180°

m∠FJG+m∠JGF+m∠JFG=180°

⇒ 39°+13°+m∠JFG=180°

⇒ m∠JFG=180°-39°-13°=128°

As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair

⇒ m∠JFG+m∠EFG=180°

⇒ 128°+m∠EFG=180°

⇒ m∠EFG=52°

The measure of ∠EFG is 52°

6 0
3 years ago
I need help with this problem
marishachu [46]

True

∠2 and ∠5 are both vertical at the vertex of the 2 straight lines



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determine the length of side y, to the nearest tenth, in each of the following triangles. Please show work
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The final answer is 10.9

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Jeff is 15 years from retiring. He opens an account at the First American Bank. He plans to deposit $1,406.14 each month into th
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