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VARVARA [1.3K]
3 years ago
13

Please help me answer this question. First to answer will be marked braineist. NO WORK NESSACARY. Thank you ☺️

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Lets check the first point (0,6)


3*0+4=4  no good

0+6 =6  good

0^2+6 =6 good

6 * (7/6) ^0 =6  good


Lets check the second point (1,7)

3*1+4=  we don't care since it didn't work for (0,6)

1+6 =7

1^2+6 =7

6 * (7/6) ^1 =7


Lets check the third point (2,10)


3x+4=  we still don't care

2+6 = 8 no good

2^2+6 =10  good

6 * (7/6) ^2 =6 * 49/36 =49/6  no good


f(x) = x^2 +6


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The 5 - number summary of the distribution obtained from the boxplot is :

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Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

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I just need numbers 23 and 24
kobusy [5.1K]
23; 20+4+9+ 28
he can estimate by rounding the numbers
24;19.99+4.19+8.50+27.75=
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