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melisa1 [442]
3 years ago
10

The equation of a line is given by y=m+b. Solve for M

Mathematics
1 answer:
padilas [110]3 years ago
6 0

Step-by-step explanation:

M =<u> y</u>

b

That is the answer

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A bag contains 9 marbles: 4 are green, 3 are red, and 2 are blue. Deshaun chooses a marble at random, and without putting it bac
nexus9112 [7]

Step-by-step explanation:

Total marbles = 9 + 4 + 3 + 2 = 18

Probability of both red marbles = 3 / 18 = 1/6

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Which relationship could be the one shown on the graph? I GIVE BRAINLIEST! PLS IM TIMED!!!!!!!!!!!!
zmey [24]

Answer:

Im kinda sure its a because

Step-by-step explanation:

through points<u> (2, 19)</u> A says Misaki had<u> </u><u>2 </u>identical pencils that weighed a total of <u>19 </u>grams, where x is the number of pencils and y is the total weight of the pencils.

8 0
3 years ago
Read 2 more answers
LxWxH pls and thank u
lutik1710 [3]

l = 2in

b = h = 3in

now , Lbh

= 2×3×3

= 18 in³

i hope this helps

4 0
3 years ago
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Step2247 [10]

Answer:

20 sq in

Step-by-step explanation:

formula is (base * height)/2 so plug it in:

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8 0
2 years ago
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
4 years ago
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