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Pls help me!!<br> Which two equations are equivalent?<br> y= 1/2x+3<br> y=x+6<br> 2y=x+6

Zigmanuir [339]

Answer:

first and third

Step-by-step explanation:

Consider

y = $\frac{1}{2}$ x + 3 ( multiply through by 2 )

2y = x + 6 ← third equation

4 0

3 years ago

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What are the coordinates of point P on the coordinate grid below?

Alik [6]

If you look carefully at the grid, you will see that each increment is by 1/8.

That means that for the x-coordinate of P, you can count from -4/8 to get -5/8.

For the y-coordinate, you can count up from 0 to get 3/8.

Then, the answer is (-5/8, 3/8), or the third answer.

7 0

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

ElenaW [278]

9514 1404 393

Answer:

-8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

8y = 5x +11 . . . . . add 5x

y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

-1/(5/8) = -8/5 . . . . slope of perpendicular line

4 0

3 years ago

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago

How many fractions is equivalent to 4/6

ValentinkaMS [17]

The fractions are 2/3

3 0

4 years ago

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