All categories

3 years ago

Natural selection of favorable adaptations in organisms often results in

Biology

2 answers:

MrRissso [65]3 years ago

7 0

This results in Evolution. Organisms will adapt to their surroundings in the form of evolution.

spayn [35]3 years ago

5 0

Answer:

<h2>Evolution.</h2>

Explanation:

Natural selection is a evolution theory by Charles Darwin. It refers to the survival ability that species have, which allow them to reproduce. So, basically, those species that don't are able to adapt, they will disappear; and those that are able to adapt will evolve.

You might be interested in

What action do researchers take to make advances in science?

iogann1982 [59]

They share their experimental results with other researchers

3 0

3 years ago

Read 2 more answers

Which plants produce leaves? (Select all that apply.) a. Gametophytes of bryophytes b. Gametophytes of seedless vascular plants

bixtya [17]

Answer:

a. Gametophytes of bryophytes

d. Sporophytes of seedless vascular plants

Explanation:

Bryophytes are non-vascular plants. The plant body is haploid gametophyte which is its dominant phase and bears sex organs. The gametophyte may be leafy as in moss and may be with thalloid as in liverworts.

Pteridophytes are seedless, true vascular plants. The plant body is the diploid sporophyte. The sporophyte is differentiated into true leaves, stem and roots.

6 0

3 years ago

The alveolar cell that secretes pulmonary surfactant is the

luda_lava [24]

<span>Type 2 alveolar cells or pneumocytes are the cells responsible for secreting pulmonary surfactant. Their function is important as the pulmonary surfactant is required to decrease surface tension within the alveoli. They are capable of cell division which in turn produces more of these alveolar cells when there is damage to the lung.</span>

5 0

3 years ago

Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago

Please place the following vessels in the correct order to represent the arterial circulation leading up to the glomerulus.

Ymorist [56]

The following vessels are connected as below:

aorta ->renal arteries ->segmental arteries ->interlobular arteries ->arcuate arteries ->cortical radiata ->afferent arteries ->glomerulus.

1) aorta : arises from heart which carry blood from heart to the rest of the body

2) renal artery :it arises from the aorta which carry blood to kidney .it carry unfiltered blood .

3)segmental arteries : it arises from renal artery .it has 5 branches or segments.

4)interlobular arteries : it arises from segmental arteries. the interlobular arteries pass directly outward between the medullary rays to reach the fibrous tunic ,where they end in the capillary network of this part.

5)Arcuate arteries: it arises from interlobular arteries .it is also known as arciform arteries, are vessels of the renal circulation. they are located at the border of the renal cortex and renal medulla.

6) cortical radiata: it arises from arcuate arteries.

7) afferent arteries: it arises from interlobular arteries and also connects to glomerulus. they are a group of blood vessels that supply the nephrons in many excretory systems .they play a important role in regulation of blood vessels.

8) glomerulus : it connects from afferent arteries.it is the filtering unit of kidney ,is a specialised bundle of capillaries that are uniquely situated between two resistance vessels.

Disclaimer: the given question is incomplete means it contains incomplete data .the correct question is given below.

Question: Please Place The Following Vessels In The Correct Order To Represent The Arterial Circulation Leading Up To The Glomerulus. Aorta Interlobar Artery Segmental Artery Afferent Arteriole Cortical Radiate Renal Artery Arcuate Artery Glomerulus

Please place the following vessels in the correct order to represent the arterial circulation leading up to the glomerulus.

Aorta

Interlobar artery

Segmental artery

Afferent arteriole

Cortical radiate

Renal artery

Arcuate artery

Glomerulus

Learn more about blood vessels here :

brainly.com/question/11763276

#SPJ4

5 0

2 years ago