<h3>
Answer: 6 mph</h3>
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Explanation:
distance = rate*time
90 = r*t
where r is the slower speed and t is the time it takes when going that slower speed.
If r is bumped up 24 mph faster, to r+24, then Santos takes t-12 hours to get there. The second equation is
90 = (r+24)(t-12)
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We can solve the first equation for r to get r = 90/t
Then plug this into the second equation and do a bit of algebra
90 = (r+24)(t-12)
90 = (90/t+24)*(t-12)
90 = 90 - 1080/t + 24t - 288
90t = 90t - 1080 + 24t^2 - 288t
0 = 90t - 1080 + 24t^2 - 288t-90t
0 = 24t^2 - 288t - 1080
24t^2 - 288t - 1080 = 0
If you apply the quadratic formula, then you should get the two solutions t = -3 and t = 15. Due to time constraints, I'll skip these steps.
We'll ignore the negative t value. It makes no sense to have a negative time.
So we focus on t = 15 as the only solution.
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If t = 15, then,
r = 90/t
r = 90/15
r = 6
Santos rode his bike at <u>6 mph</u> at first. Going this speed means he takes 15 hours.
If he rode 24 mph faster, at 6+24 = 30 mph, then he would ride for 15-12 = 3 hours instead. Note that 90/30 = 3.
<span>The answer is: 1, 2, 7, 14 .
</span>_____________________________________________________
Explanation:
________________________________________________
FIrst, list all the factors of 42 (positive integers):
________________________________________________________
1, 42
2, 21,
3, 14,
6, 7
_________________________________________________
Then list all the factors of 28 (positive integers):
____________________________________________________
<span> 1, 28
2, 14,
4, 7
</span>_____________________________________________________
Now, list all numbers that occur for BOTH the factors of "28" AND the factors of "42"
_____________________________________________________
1, 2, 7, 14
_____________________________________________________
The answer is: 1, 2, 7, 14 .
_______________________________________________________
Answer:
38.6 m/s
Step-by-step explanation:
The motion of the ball is a projectile motion, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction
Therefore we have to analyze the horizontal and vertical motion separately.
Along the horizontal direction, the velocity is constant during the motion, since there are no forces acting in this direction. So the horizontal velocity 3 seconds after the launch will be the same as the velocity at the launch:

The vertical velocity instead changes according to the suvat equation:

where
is the initial vertical velocity
is the acceleration due to gravity
t is the time
Therefore, after t = 3 s,

So the velocity after 3 seconds is < 25, -29.4 > m/s. The magnitude of the velocity is

Answer:
.
Step-by-step explanation:
Start by finding the slope of the line perpendicular to
.
The slope of
is
.
In a plane, if two lines are perpendicular to one another, the product of their slopes would be
.
Let
denote the slope of the line perpendicular to
. The expression
would denote the product of the slopes of these two lines.
Since these two lines are perpendicular to one another,
. Solve for
:
.
The
is a point on the requested line. (That is,
and
.) The slope of that line is found to be
. The equation of that line in the point-slope form would be:
.
Rewrite this point-slope form equation into the slope-intercept form:
.
Step-by-step explanation:
I am doing the same math and I have no idea one nobody is helping me :/ there just looking at my problem and saying the wrong number :((