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3 years ago

2x2 + 13x - 7 factor the polynomial

1 answer:

4 0

2x2 + 13x - 7
=(2x - 1)(x + 7)

You need the two outside terms and two inside terms to add to 13x. And the last term in each of the parentheses to multiply to -7.

ANSWER: (2x - 1)(x + 7)

Hope this helps! :)

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Step-by-step explanation:

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3 years ago

Can some one solve this pls<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D_0%20%5Cfrac%7B

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Step-by-step explanation:

Hello, please consider the following.

$x(t)=sin(t)\\\\dx=cos(t)dt\\\\\text{For x = }\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2} \text{ we have } t = \dfrac{\pi}{4}$

So, we can write.

$\displaystyle \int\limits^{\dfrac{1}{\sqrt{2}}}_0 {\dfrac{1}{\sqrt{1-x^2}}} \, dx =\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{1-sin^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{cos^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{cos(t)}} \, dt \\\\=\int\limits^{\dfrac{\pi}{4}}_0 {1} \, dt\\\\=\large \boxed{\sf \bf \dfrac{\pi}{4}}$

Thank you

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3 years ago

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