F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Yes, I believe they are equivalent because if you were to solve -1/4(10t-15) it would equal -2t+3
C.) x = -4 is the correct answer
Step-by-step explanation:
In order to solve the equation we have to isolate x on one side of equation
Given
7x + 6 = -22
Subtracting 6 from both sides

Dividing both sides by 7

Hence,
C.) x = -4 is the correct answer
Keywords: Linear equation
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Answer:
Step-by-step explanation:
See attachment.
The change from x to (x-4) moved the function to the right by 4. The - 5 moved it down by 5 (as measured from the crossover/inflection point.