Answer: $122.50
<u>Step-by-step explanation:</u>
In Out
8:00 12:00 = 4 hours
12:45 17:30 =<u> 4.75 hours </u>
Total 8.75 hours
8.75 hours x $14/hr = $122.50
Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:
17:30 → 16:90
- 12:45 -<u> 12:45 </u>
4: 45
4 hours 45 minutes = 
= 4.75 hours
If there are multiple operations at the same level on the order of operations off from left to right and you work like this first noticed that there are no parentheses or exponents so we moved to multiplication and division with any sense of parentheses
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t
Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
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The volume of a cylinder is represented by:
We know that r is equal to
, and d in this case is 9 in. Therefore, r = 4.5 in.
Then, using 3.14 for
, and 15 in. for height, we can solve for the volume of the cylinder:
By using this equation, we were able to determine that the volume of this cylinder is
.
