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Oduvanchick [21]
3 years ago
12

A woman standing on a hill sees a flagpole that she knows is 40 ft tall. the angle of depression to the bottom of the pole is 14

°, and the angle of elevation to the top of the pole is 18°. find her distance x from the pole.
Mathematics
1 answer:
NemiM [27]3 years ago
6 0
Let distance form the pole = x  and height of the hill = y ft

now we can set up 2 equayions 
tan 18 = (40-y)/x
tan 14 = y/x

from second equation y = sxtan14  so we have:-
 tan 18  = ( 40 - x tan 14) /  x

x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40

x   = 40 / (tan18 + tan 14)  =  69.66 feet Answer



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A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
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Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

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Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

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Step-by-step explanation:

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