Answer:
(3)(c) + 43 ≥ 100
Step-by-step explanation:
Given:
Total number of friends = 3 friends
Number of card already have = 43
Total number of card at least want to collect = 100
Find:
Inequality
Computation:
Assume;
Same number of card each friend collect = c
Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have
Total number of card at least want to collect ≤ (3)(c) + 43
100 ≤ (3)(c) + 43
(3)(c) + 43 ≥ 100
Answer:
.07 * 15.25 = 1.0675
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
If you look at the graph where it says 0 minutes which would be on the origin and look up, it will be at 1,000 people which means 1,000 people were there before anything started.
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
Answer:
m < EAD = 29 degrees
m < CAB = 119 degrees
Given :
The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees
Solution:
1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)
2. m<BAC + m<EAC = 180 degrees (sum of linear pair)
3. m<CAB = 180 degrees - m<EAC
4. Equation 1: m<CAB = m<EAF = 119 degrees
5. m<EAF = m<EAD + m< DAF
6. m<EAD = m<EAF - m<DAF
7. m<EAD = 119 degrees-90 degrees = 29 degrees
Hope this helps!!! :)
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