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masya89 [10]
3 years ago
11

Can someone help me with this question "Given the triangle below, what is m (angle) < B, rounded to the nearest tenth?

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0
The answer
the sum of the angles in a triangle is always 180°
m < B + m < A + m < C = 180°,  
let's find m < B, 
by applying sinus rule 
 14/sinB=10/sinC, so sinB= 10xsinB = 14 x sinC and therefore, 
sinB=( 14/10 )sinC =7/2 sin 36° =0.82, so arcsinB=55.08°
the answer is C 55.4°



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Answer:

x = ±2√5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  • Left to Right  

Equality Properties

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

4x² - 5 = 75

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 5 on both sides:                                    4x² = 80
  2. [Division Property of Equality] Divide 4 on both sides:                                  x² = 20
  3. [Equality Property] Square root both sides:                                                    x = ±2√5
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b. Equivalent ratios
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Let's simplify step-by-step.

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Distribute the Negative Sign:

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Combine Like Terms:

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